How much time does it take for the Porsche to catch the Honda?

Two cars, a Porsche and a Honda, are traveling in the same direction, although the Porsche is 184 m behind the Honda. The speed of the Porsche is 23.9 m/s and the speed of the Honda is 17.9 m/s. How much time does it take for the Porsche to catch the Honda? [Hint: What must be true about the displacements of the two cars when they meet?]

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3 Responses to 'How much time does it take for the Porsche to catch the Honda?'

1. Slaggers - October 15th, 2009 at 4:37 pm

   Hey!

   Here’s the entire answer to your question.

   Let’s first identify the values we’re given:

   d = distance Porsche is behind Honda = 184 m

   V = speed of Porsche = 23.9 m/s

   v = speed of Honda = 17.9 m/s

   The “hint” in the problem asks what must be true about the displacements of the cars when they meet? Well, the displacements must be EQUAL if they meet:

   displacement of Honda = displacement of Porsche

   or

   d(Honda) = d(Porsche)

   Now let’s figure out what these displacements are. Assume that the INITIAL position of the Porsche is d = 0. Then:

   d(Honda) = d + v*t

   d(Porsche) = V*t

   Now we equate these two values:

   d + v*t = V*t

   Here t = time, which is what we’re solving for. Rearranging terms to solve for t:

   t = d / (V-v)

   = 184 m / (23.9 m/s - 17.9 m/s)

   = 30.66 seconds

   So the Porsche will catch up to the Honda in 30.66 seconds. That’s your answer!

   anaGah.

2. lunar_rick - October 16th, 2009 at 7:27 pm

   The basic formula would be vp * t = vh * t + x
   Rewrite as t = x / (vp - vh) = 184 / (23.9 - 17.9) = 184 / 6 = 30.6 seconds.

3. leomir - October 20th, 2009 at 2:17 am

   Tiempo de alcance:

   Ta = d / ( V1 - V2)…………………( V1 > V2 )

   Ta = 184 / (23,9 - 17,9) = 30,67s

   Suerte!!! consultas:

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